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Old 04-28-2010, 05:00 AM   #1 (permalink)
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Default Push a new screen on a menu item select - Beginner help

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Guys i am very new to the world of blackberry. I have one question now. I have created a small application where i will have a MAIN screen displaying some components. But when the user presses the menu and select a menu option i need to push another screen containing different set of components.My sample code is as follows


Code:
public class ContactMain extends UiApplication {

	public static void main(String[] args) {

		ContactMain contactMain = new ContactMain();
		contactMain.enterEventDispatcher();
	}

	public ContactMain() {
		pushScreen(new ContactMainScreen());
	}

}


--------------------------


final class ContactMainScreen extends MainScreen {

	//components declaration


	public ContactMainScreen() {

          //initialize components

	}

	protected void makeMenu(Menu menu, int instance) {
		menu.add(addContact);
		
	}

	private MenuItem addContact = new MenuItem("Add Contact", 110, 10)                      
        {
		public void run() {
			UiApplication.getUiApplication().(new ContactAddScreen());
		}
	};

}



----------------------------------------




final class ContactAddScreen extends MainScreen {


	//components declaration

	public ContactAddScreen() {

		    //initialize components

	}
}
--------------------------------------------------

But as soon as i press the menu i am getting a null pointer exception .

please help

Last edited by karthikus : 04-28-2010 at 05:08 AM.
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Old 04-28-2010, 08:20 AM   #2 (permalink)
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Default

This:

UiApplication.getUiApplication().(new ContactAddScreen());

Should be:

UiApplication.getUiApplication().pushScreen(new ContactAddScreen());
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