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Old 06-13-2011, 07:49 AM   #1 (permalink)
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Hello,

I am working in blackberry using eclipse

I calculated prayer times using following code:-

public void setCurrentDateTime() {
currentDate = new Date();
Calendar c = Calendar.getInstance();
c.setTime(currentDate);
tz = TimeZone.getDefault();
c.setTimeZone(tz);

// calculate day of the year (rather tricky!)
c.set(Calendar.MONTH, 0);
c.set(Calendar.DAY_OF_MONTH, 1);
c.set(Calendar.HOUR, 0);
c.set(Calendar.MINUTE, 0);
c.set(Calendar.SECOND, 0);
Date JanFirst = c.getTime();
long millis = currentDate.getTime()-JanFirst.getTime();

DayOfTheYear = (int) (millis / 1000 / 3600 / 24);
}

public void calculatePrayerTimes() {
// Sh=1 (Shafii) - Sh=2 (Hanafi)

int Sh = settings.juristicMethod+1;

int J = DayOfTheYear;
double D; // Solar Declination angle (degrees)
double T; // Equation of Time (minutes)
double B; // Latitude (degrees)
double L; // Longitude (degrees)
double R; // Reference longitude (degrees)


// method described here:
// http://qvezst.googlepages.com/Prayer...wareDevelo.doc

double TZ = HourMinute.getTimeZoneOffset();

double beta = 2.0* Math.PI * J / 365.0;

L = longitude;
B = latitude;
//////////calculate Solar Declination angle (degrees)////////////////////////
D = 180.0 / Math.PI * (
0.006918
- 0.399912*Math.cos(beta)
+ 0.070257*Math.sin(beta)
- 0.006758*Math.cos(2.0*beta)
+ 0.000907*Math.sin(2.0*beta)
- 0.002697*Math.cos(3.0*beta)
+ 0.001480*Math.sin(3.0*beta));
////////calculate Equation of Time (minutes)/////////////////////////////
T = 229.18 * (
0.000075
+ 0.001868*Math.cos(beta)
- 0.032077*Math.sin(beta)
- 0.014615*Math.cos(2.0*beta)
- 0.040849*Math.sin(2.0*beta));
/////////////calculate Reference longitude (degrees)/////////////////////
R = 15.0 *TZ;
double Gd =18;// getDawnAngle();
double Gn = 18;//getDuskAngle();
double H = altitude;
double Dhuhr = 12+(R-L)/15-T/60;
double U = 180.0 / Math.PI / 15.0 *
mMath.acos(
(Math.sin((-0.8333 - 0.0347*sign(H)*Math.sqrt(Math.abs(H)))*Math.PI/180.0)
- Math.sin(D*Math.PI/180.0)*Math.sin(B*Math.PI/180.0))
/
(Math.cos(D*Math.PI/180.0)*Math.cos(B*Math.PI/180.0))
);

double Vd = 180.0 / 15.0 / Math.PI *
mMath.acos(
(-Math.sin(Gd*Math.PI/180.0)-Math.sin(D*Math.PI/180.0)*Math.sin(B*Math.PI/180.0))
/
(Math.cos(D*Math.PI/180.0)*Math.cos(B*Math.PI/180.0))
);
double Vn = 0;
if (Gn < 25) {
Vn = 180.0 / 15.0 / Math.PI *
mMath.acos(
(-Math.sin(Gn*Math.PI/180.0)-Math.sin(D*Math.PI/180.0)*Math.sin(B*Math.PI/180.0))
/
(Math.cos(D*Math.PI/180.0)*Math.cos(B*Math.PI/180.0))
);
}
else {
Vn = Gn/60;
}
double W = 180.0 / 15.0 / Math.PI *
mMath.acos(
(Math.sin( mMath.acotan( Sh + Math.tan(Math.abs(B-D)*Math.PI/180.0) ) )
- Math.sin(D*Math.PI/180.0)*Math.sin(B*Math.PI/180.0))
/
(Math.cos(D*Math.PI/180.0)*Math.cos(B*Math.PI/180.0))
);


mins[0]=getMinutes(Dhuhr-Vd); //Fajr
mins[1]=getMinutes(Dhuhr-U); //Al Sharuq
mins[2]=getMinutes(Dhuhr); //Dhuhr
mins[3]=getMinutes(Dhuhr+W); //Asr
mins[4]=getMinutes(Dhuhr+U); //Margrib
if (Gn < 25)
mins[5]=getMinutes(Dhuhr+Vn);
else
mins[5]=getMinutes(Dhuhr+U+Vn);


}
public String getPrayerTimes(boolean twentyFourHourClock, double minutes){
String str = "";
int mins = ((int)Math.max(0,minutes));
String minsStr = String.valueOf(mins%60);
if ((mins%60) < 10) minsStr = "0" + minsStr;
int hrs = mins/60;
if (!twentyFourHourClock) {
if (hrs > 12) hrs -= 12;
}
str = String.valueOf(hrs) + ":" + minsStr;
return str;
}
public double getMinutes(double hrs) {
double minutesSinceMidnight;
if (hrs>=24) hrs-=24;
if (hrs<0) hrs+= 24;
return minutesSinceMidnight = (hrs*60.0);
}

for latitude & longitude i use this webservice :
http://local.yahooapis.com/MapsServi...e&city=toronto

i am giving altitude as 0.0 always

I get wrong prayer times...Is some thing wrong with this code or i am missing some thing.. why this code gives me wrong prayer times??
any one have any idea?
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